Given the head of a singly linked list, reverse the list, and return the reversed list.
Input: head = [1,2,3,4,5]
Output: [5,4,3,2,1]
Input: head = [1,2]
Output: [2,1]
Input: head = []
Output: []
For this problem, the LinkedList node is defined as:
JavaScript:
class ListNode {
constructor(val, next) {
this.val = (val===undefined ? 0 : val)
this.next = (next===undefined ? null : next)
}
}
Python:
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
No output yet...